1/2Kx^2

Hookes law gives us the force we need to find elastic potential energy. Please answer all three parts in depth explaining each answer.

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When the mass in at the farthest distance and stationary 12 mv 2 0 so 12 kx 2 E and x is at a.

. Or if you miswrite and it should be. If we had instead defined the force as F -2kx then U would be kx². Youll get a detailed solution from a subject matter expert that helps you learn core concepts.

September 1 2017 aid. U 1 2 kx2 U 1 2 k x 2. The spring constant is the measure of stiffness of a spring.

Plug in x_1 and x_2 to the derivatives and you will have the respective slopes of the tangent at points x_1. Solve for x U12kx2. 12kx2 what is k 12kx2 what is k.

Both 12Fx and 12 kx2 are correct and equivalent to each other. Potential energy 12spring constant distance from equilibrium2. The derivative gives the slope of the tangent to the parabolas y fx and y gx.

Like all work and energy the unit of potential energy is the Joule J where 1 J 1Nm 1 kg m2s2. The potential energy can be found using the formula. U 12kx2 U 12 750 Nm 040 m 2 U 060 Nm U 060 J The elastic potential energy stored by the spring when it is has been.

1 2 kx2 U 1 2 k x 2 U. So the above equation means that the amount of work done is equal to the change. Rewrite the equation as 1 2 kx2 U 1 2 k x 2 U.

This problem has been solved. This force leads to the potential energy U 12 kx². X 2 14142 k 0.

Multiply both sides of the equation by 2 2. W U W on the LHS side stands for Work. Advertisement Advertisement New questions in Mathematics.

4 times x is at most 12 Pls help fast 10 pointsNeed answer. Math Answers Mathematics Is The Key And Door To The Sciences. Looking at a graph of force versus.

And U on the RHS side stands for internal energy. Alternatively you can assume that the spring in equilibrium has a. The slight preference for 12 kx2 is down simply to the fact that you need only measure one variable- the dispalcement x.

When the mass is in the middle 12 kx 2 0 so 12 mv 2 E and v is at a maximum.

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Solved A Marble Is Attached To A Compressed Horizontal Spring And Is Then Released Which Equation Correctly Shows The Conservation Of Mechanical Energy For This System 1 Point Mgh 1 2kx 2 Mgh Kx 2 1 2mv 2 1 2kx 2 1 2mv 2 Kx 2